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David Brewster

Sir David Brewster

A course in two strands: the life of a Border schoolmaster’s son who trained for the pulpit and became Scotland’s leading experimental physicist, and the optics he measured, from the polarizing angle and stressed glass to the kaleidoscope and the stereoscope.

Born 11 December 1781, Jedburgh Died 10 February 1868, Allerly, Melrose Brewster’s law read 16 March 1815 Level advanced undergraduate
Reflectance of glass (n = 1.5) for the two polarizations. At tan θ = n, about 56.3°, the p-polarized reflection vanishes and reflected light is fully polarized.
Lesson 00

How to use this course

David Brewster is remembered by students for a single angle and by the public for a toy. Both memories are accurate and both are too small. Between 1811 and 1819 he carried out the most extensive experimental survey of polarized light of his era. He found the law of polarization by reflection, showed that strain makes glass doubly refracting, and sorted hundreds of crystals into optical classes that matched their geometry. He also edited an encyclopaedia, helped found the British Association for the Advancement of Science, wrote the standard Victorian life of Isaac Newton, and led two Scottish universities.

Prerequisites for Part II
  • Geometric optics: Snell’s law, thin lenses, prisms.
  • Electromagnetic waves at the level of a second-year course: polarization, boundary conditions.
  • Linear algebra: symmetric matrices, eigenvalues, rotations and reflections in the plane.
  • For Lesson 07, the idea of a stress tensor and principal stresses.

Brewster worked by measurement and generalisation rather than by theory, and he never accepted the wave theory of light that explained his own laws. Part II therefore pairs each of his empirical results with the modern derivation, usually due to Augustin-Jean Fresnel or later physicists. Each technical lesson opens with a paragraph for the general reader, then gives statements, derivations and exercises with folded solutions.

Reference

Timeline

1781Born 11 December in Jedburgh, Roxburghshire, third of six children of James Brewster, rector of the grammar school, and Margaret Key.
c. 1794Enters the University of Edinburgh aged 12.
1799Henry Brougham interests him in the diffraction of light.
1800MA, Edinburgh. Studies divinity and is later licensed to preach in the Church of Scotland.
1802–03Edits the Edinburgh Magazine.
1807Becomes editor of the Edinburgh Encyclopaedia (published 1808–1830). LLD from Marischal College, Aberdeen.
1808Elected to the Royal Society of Edinburgh.
1810Marries Juliet Macpherson.
1811Proposes building large lenses from separate zones.
181516 March: the law of polarization by reflection is read to the Royal Society. Elected FRS; Copley Medal. First kaleidoscope effects.
1815–16Discovers double refraction in strained and heated glass.
1816Half of a 3000-franc prize of the French Institute.
1817Kaleidoscope patent, granted July 1817.
1818Rumford Medal. Classifies crystals by number of optic axes; paper on the absorption of polarized light by crystals.
1819Founds the Edinburgh Philosophical Journal with Robert Jameson. Treatise on the Kaleidoscope. General Secretary of the RSE (to 1828).
1830Royal Medal of the Royal Society.
1831Knighted; Royal Guelphic Order. First meeting of the British Association at York. Life of Sir Isaac Newton.
1832Letters on Natural Magic, addressed to Sir Walter Scott.
1833–34Absorption lines of nitrous gas; atmospheric lines in the solar spectrum.
1838Principal of the United College of St Salvator and St Leonard, St Andrews.
1843Joins the Free Church of Scotland at the Disruption.
1849Lenticular stereoscope. Foreign associate of the Institut de France. President of the British Association.
1851His stereoscopes, made by Jules Duboscq, are shown at the Great Exhibition.
1854–55More Worlds than One; Memoirs of the Life, Writings, and Discoveries of Sir Isaac Newton.
1857Marries Jane Kirk Purnell in Nice.
1859Principal of the University of Edinburgh.
1860With John Hall Gladstone, On the lines of the solar spectrum.
1864President of the Royal Society of Edinburgh.
1868Dies 10 February at Allerly, near Melrose, aged 86. Buried at Melrose Abbey.
Part I · Formation
Lesson 01

Jedburgh and Edinburgh, 1781–1800

David Brewster was born on 11 December 1781 in Jedburgh, a small Border town in Roxburghshire. His father, James Brewster, was rector of the town’s grammar school and a respected teacher. His mother, Margaret Key, died in 1790, when he was eight. He was the third of six children, and three of his brothers, James, George and Patrick, became ministers of the Church of Scotland. The family expected David to follow them.

As a boy he built a telescope with the help of a local self-taught astronomer and instrument maker, James Veitch of Inchbonny. At twelve he matriculated at the University of Edinburgh, a normal age for a Scottish student then. He took his MA in 1800. In 1799 his fellow student Henry Brougham, later Lord Chancellor, drew him into the study of the diffraction of light, the subject that would occupy him for the rest of his life.

Lesson 02

Preacher, tutor, editor, 1800–1811

After his MA Brewster studied divinity and was licensed to preach in the Church of Scotland. He found preaching an ordeal and did not seek a parish. Instead he supported himself as a private tutor and, increasingly, as a writer and editor. He wrote for the Edinburgh Magazine from 1799 and edited it in 1802 and 1803. In 1804 he published a history of freemasonry.

In 1807 he became editor of the Edinburgh Encyclopaedia, a vast project that appeared in parts from 1808 to 1830 and to which he contributed many of the scientific articles himself. The same year Marischal College, Aberdeen, gave him an honorary LLD. He was elected to the Royal Society of Edinburgh in 1808, and on 31 July 1810 he married Juliet Macpherson. They had several children; their son Charles drowned in 1828.

Editing gave Brewster a living, a wide reading of current science, and a lifelong habit of controversy in print. It did not give him a laboratory. His most important experiments were made at home, with crystals, glass plates, a lamp and the sky.

Lesson 03

The polarization years, 1811–1819

In 1808 Étienne-Louis Malus in Paris discovered that light reflected from glass is polarized: viewed through a calcite crystal, its two images change in brightness as the crystal turns. Malus died in 1812. Brewster, then in his thirties and working largely alone in Scotland, took up the subject with great energy, measuring reflection from dozens of substances and the behaviour of light in crystals.

In a paper read to the Royal Society on 16 March 1815 he announced that the angle of complete polarization depends on the refractive index alone: its tangent equals the index (Lesson 04). The same year he was elected a Fellow of the Royal Society and received its Copley Medal. In 1815 and 1816 he showed that glass under pressure or unequal heating becomes doubly refracting and shows coloured fringes in polarized light (Lesson 07). From 1813 to 1818 he examined hundreds of crystals and found that they fall into two optical classes, with one or two axes of no double refraction, matching their crystallographic symmetry (Lesson 06). The Royal Society awarded him the Rumford Medal in 1818.

His work on multiple reflections between mirrors, begun in 1814, gave him the kaleidoscope in 1815 (Lesson 08). He patented it in 1817, but the design was so easy to copy that he made little money from it. In 1819 he founded the Edinburgh Philosophical Journal with the mineralogist Robert Jameson and became General Secretary of the Royal Society of Edinburgh.

Part II · The physics
Lesson 04

Brewster’s law

For the general reader. Light reflected from water or glass is partly polarized, which is why polarizing sunglasses cut glare. At one particular angle the reflected light is completely polarized. Brewster found by measurement that this angle depends only on how strongly the material bends light: its tangent is the refractive index. Fresnel’s wave theory explained the law a few years later.

Goals
  • State Brewster’s law and its geometric form.
  • Derive it from the Fresnel equations.
  • Understand why the p-polarized reflection vanishes.
Brewster’s law (1815)

When light in a medium of index \(n_1\) is reflected from a non-absorbing medium of index \(n_2\), the reflected light is completely polarized, with its electric field perpendicular to the plane of incidence, at the angle of incidence \(\theta_B\) given by

\[ \tan\theta_B=\frac{n_2}{n_1}. \]

At this angle the reflected and refracted rays are perpendicular: \(\theta_B+\theta_t=\tfrac{\pi}{2}\).

Brewster stated the law in the form “the index of refraction is the tangent of the angle of polarisation”. He found it by measuring polarizing angles for many substances, and observed that for each the reflected and refracted rays met at a right angle.

Derivation from the Fresnel equations

For non-magnetic media, the amplitude reflection coefficients for the field perpendicular (s) and parallel (p) to the plane of incidence are

\[ r_s=-\frac{\sin(\theta_i-\theta_t)}{\sin(\theta_i+\theta_t)},\qquad r_p=\frac{\tan(\theta_i-\theta_t)}{\tan(\theta_i+\theta_t)}, \]

where \(n_1\sin\theta_i=n_2\sin\theta_t\). (Sign conventions for \(r_p\) differ between textbooks; the reflectances \(R=|r|^2\) do not.) The coefficient \(r_p\) vanishes when \(\tan(\theta_i+\theta_t)\) is infinite, that is when \(\theta_i+\theta_t=\pi/2\). Then \(\sin\theta_t=\cos\theta_i\), and Snell’s law gives \(n_1\sin\theta_i=n_2\cos\theta_i\), which is Brewster’s law.

Physical picture

The reflected wave is radiated by dipoles in the second medium, oscillating along the field of the refracted wave. For p-polarization that field lies in the plane of incidence, perpendicular to the refracted ray. If the reflected ray is perpendicular to the refracted ray, it points along the dipole axis, and a dipole does not radiate along its own axis. No p-light is reflected.

Exercise 4.1Find Brewster’s angle for light in air striking water (\(n=1.333\)), crown glass (\(n=1.5\)) and diamond (\(n=2.42\)).

Show solution
\(\arctan 1.333\approx53.1^\circ\), \(\arctan1.5\approx56.3^\circ\), \(\arctan2.42\approx67.5^\circ\).

Exercise 4.2Show that at Brewster’s angle the s-reflectance is \(R_s=\cos^2 2\theta_B=\left(\dfrac{n^2-1}{n^2+1}\right)^2\), with \(n=n_2/n_1\). Evaluate it for glass.

Show solution
With \(\theta_i+\theta_t=\pi/2\), \(r_s=-\sin(\theta_B-\theta_t)=-\sin(2\theta_B-\pi/2)=\cos2\theta_B\). Since \(\tan\theta_B=n\), \(\cos2\theta_B=\frac{1-n^2}{1+n^2}\). For \(n=1.5\), \(R_s=(1.25/3.25)^2\approx0.148\): only about 15% of the s-light is reflected, which is why one reflection gives intense polarization but weak light.

Exercise 4.3Light inside glass meets the glass–air surface. Find the internal Brewster angle and show it is the refraction angle \(\theta_t\) of the external case.

Show solution
Now \(\tan\theta_B'=1/n\), so \(\theta_B'=\pi/2-\theta_B\approx33.7^\circ\) for \(n=1.5\). Since \(\theta_t=\pi/2-\theta_B\) in the external case, the two coincide. Light entering a parallel plate at Brewster’s angle meets the second face at its internal Brewster angle, so p-light passes both faces without loss.
Lesson 05

Piles of plates and Brewster windows

For the general reader. One reflection at Brewster’s angle gives perfectly polarized but faint light. Brewster studied the light transmitted through a stack of glass plates, which loses a little of one polarization at each surface and none of the other. With enough plates the transmitted beam becomes strongly polarized. The same principle now keeps laser beams polarized.

Goals
  • Compute the degree of polarization transmitted by a pile of plates.
  • Understand Brewster windows in lasers.
  • See the limits of the simple model.
Pile of plates (no multiple reflections, no absorption)

For \(k\) parallel plates of index \(n\) tilted at \(\theta_B\), the transmittances for unpolarized input are

\[ T_p=1,\qquad T_s=(1-R_s)^{2k},\qquad R_s=\left(\frac{n^2-1}{n^2+1}\right)^2, \]

and the degree of polarization of the transmitted light is \(P=\dfrac{T_p-T_s}{T_p+T_s}=\dfrac{1-T_s}{1+T_s}\).

Each plate has two surfaces, each passing p-light completely (Exercise 4.3) and s-light with transmittance \(1-R_s\). The model neglects light reflected back and forth between surfaces, which adds some s-light to the transmitted beam and lowers \(P\) somewhat. Brewster studied the polarization of light transmitted obliquely through such piles in his early papers.

Brewster windows

In a gas laser the gain tube is often closed by windows tilted at Brewster’s angle. Light polarized in the plane of incidence passes them with no reflection loss, while the other polarization loses about 15% per surface, far more than the gain can replace. The laser therefore oscillates only in p-polarization.

Exercise 5.1Using the model, find \(P\) for 1, 5 and 10 glass plates with \(n=1.5\).

Show solution
\(1-R_s\approx0.852\). For \(k=1\), \(T_s=0.852^2\approx0.726\), \(P\approx0.16\). For \(k=5\), \(T_s\approx0.202\), \(P\approx0.66\). For \(k=10\), \(T_s\approx0.041\), \(P\approx0.92\).

Exercise 5.2A laser cavity contains a tube with two Brewster windows (four surfaces) and the beam makes many round trips. If the single-pass gain is 2%, explain why the s-polarization cannot lase.

Show solution
Per single pass, s-light crosses four surfaces with transmittance \(0.852^4\approx0.53\), a loss of 47%, far above a 2% gain. p-light crosses with essentially no loss. Only p-polarization reaches threshold.
Lesson 06

Biaxial crystals

For the general reader. A calcite crystal splits a beam of light in two, except along one special direction, its optic axis. Brewster discovered that many crystals have two such directions, not one, and that whether a crystal has none, one or two depends on the symmetry of its shape. This connected optics to crystallography and gave mineralogists a new identification tool.

Goals
  • Describe optical anisotropy by the index ellipsoid.
  • Derive the directions of the optic axes and the angle between them.
  • Match isotropic, uniaxial and biaxial optics with crystal systems.

The index ellipsoid

In a transparent non-magnetic crystal, \(\mathbf D=\varepsilon_0\boldsymbol\varepsilon\mathbf E\) with \(\boldsymbol\varepsilon\) a real symmetric tensor. In its principal axes \(\boldsymbol\varepsilon=\mathrm{diag}(n_\alpha^2,n_\beta^2,n_\gamma^2)\) with \(n_\alpha\le n_\beta\le n_\gamma\). The index ellipsoid is

\[ \frac{x^2}{n_\alpha^2}+\frac{y^2}{n_\beta^2}+\frac{z^2}{n_\gamma^2}=1. \]

For a wave travelling in direction \(\mathbf s\), cut the ellipsoid by the plane through the origin perpendicular to \(\mathbf s\). The section is an ellipse whose semi-axes are the two refractive indices for that direction, and whose axes give the two allowed directions of \(\mathbf D\). Double refraction disappears when the section is a circle.

Theorem (optic axes)

If \(n_\alpha<n_\beta<n_\gamma\), there are exactly two optic axes (directions with circular section). They lie in the \(xz\)-plane, symmetric about the \(z\)-axis, at angle \(V\) from it, where

\[ \tan V=\frac{n_\gamma}{n_\alpha}\sqrt{\frac{n_\beta^2-n_\alpha^2}{n_\gamma^2-n_\beta^2}}. \]

If two principal indices are equal the two axes merge into one (uniaxial); if all three are equal the crystal is optically isotropic.

Proof. Every central plane meets the \(xz\)-plane, and the \(y\)-axis, in lines whose radii bracket \(n_\beta\); a short argument shows that a circular section must have radius \(n_\beta\) and must contain the \(y\)-axis, whose radius is \(n_\beta\). A plane containing the \(y\)-axis and the unit vector \((\cos V,0,-\sin V)\) of the \(xz\)-plane is circular when that vector also has length \(n_\beta\) on the ellipsoid:

\[ \frac{\cos^2V}{n_\alpha^2}+\frac{\sin^2V}{n_\gamma^2}=\frac1{n_\beta^2}. \]

The normal to that plane is \((\sin V,0,\cos V)\), at angle \(V\) from \(z\). Solving for \(\tan^2V\) gives the formula; the sign choice \(\pm V\) gives two axes. ∎

Brewster’s classification

Symmetry forces the shape of \(\boldsymbol\varepsilon\). Cubic crystals (rock salt, diamond) are isotropic. Tetragonal, hexagonal and trigonal crystals (zircon, quartz, calcite) have one distinguished axis and are uniaxial. Orthorhombic, monoclinic and triclinic crystals (topaz, mica, aragonite) are biaxial. Brewster established this correspondence experimentally for hundreds of minerals between 1813 and 1819, before the tensor description existed. Fresnel’s wave-surface theory of 1821 gave the mathematical account.

Exercise 6.1A biaxial mineral has \(n_\alpha=1.52,\ n_\beta=1.58,\ n_\gamma=1.60\). Find \(2V\) measured about the \(z\)-axis.

Show solution
\(\tan V=\frac{1.60}{1.52}\sqrt{\frac{1.58^2-1.52^2}{1.60^2-1.58^2}}=1.053\sqrt{\frac{0.1860}{0.0636}}\approx1.053\times1.710\approx1.80\), so \(V\approx61^\circ\) and \(2V\approx122^\circ\). The acute angle between the axes, \(58^\circ\), is bisected by the \(x\)-axis.

Exercise 6.2Show that for small birefringence \(\tan V\approx\sqrt{\dfrac{n_\beta-n_\alpha}{n_\gamma-n_\beta}}\), and check the uniaxial limits.

Show solution
\(n_\gamma/n_\alpha\approx1\) and \(n_\beta^2-n_\alpha^2=(n_\beta-n_\alpha)(n_\beta+n_\alpha)\approx2n(n_\beta-n_\alpha)\), similarly in the denominator, so the factors \(2n\) cancel. If \(n_\beta=n_\alpha\), \(V=0\): one axis along \(z\). If \(n_\beta=n_\gamma\), \(V=90^\circ\): one axis along \(x\).

Exercise 6.3Explain by symmetry why a crystal with a threefold rotation axis along \(z\) must have \(n_\alpha=n_\beta\) in the plane perpendicular to it.

Show solution
The tensor must satisfy \(R\boldsymbol\varepsilon R^{T}=\boldsymbol\varepsilon\) for the rotation \(R\) by \(120^\circ\). Restricted to the \(xy\)-plane, a symmetric \(2\times2\) matrix commuting with a rotation by \(120^\circ\) has every direction as an eigenvector, so it is a multiple of the identity.
Lesson 07

Stressed glass and photoelasticity

For the general reader. Ordinary glass does not split light. Brewster found that squeezed, bent or unevenly heated glass does, and that viewed between crossed polarizers it shows bands of colour that map the strain. A century later engineers built transparent plastic models of bridges and gears and photographed these bands to find where they would break.

Goals
  • State the stress-optic law.
  • Compute the transmitted intensity in plane and circular polariscopes.
  • Interpret isochromatic and isoclinic fringes.
Stress-optic law (plane stress)

In a thin plate of an isotropic transparent material under plane stress with principal stresses \(\sigma_1,\sigma_2\), light travelling normal to the plate experiences two refractive indices along the principal stress directions, with

\[ n_1-n_2=C\,(\sigma_1-\sigma_2), \]

where \(C\) is the stress-optic coefficient. Through thickness \(t\) the relative phase retardation is \(\delta=\dfrac{2\pi t\,C(\sigma_1-\sigma_2)}{\lambda}\).

Stress-optic coefficients are customarily quoted in brewsters: \(1\ \text{brewster}=10^{-12}\ \mathrm{Pa}^{-1}\). Typical glasses have a few brewsters.

The polariscope

Place the plate between a polarizer and an analyzer crossed at \(90^\circ\). Let the principal stress direction make angle \(\varphi\) with the polarizer. Resolving the field along the two principal directions and recombining at the analyzer gives

\[ I=I_0\,\sin^2 2\varphi\,\sin^2\frac{\delta}{2}. \]

The intensity vanishes where \(\sin2\varphi=0\), the isoclinics, where a principal direction is parallel to the polarizer; and where \(\delta=2\pi N\), the isochromatics, along which \(\sigma_1-\sigma_2\) is constant. In white light each wavelength goes dark at a different stress, producing the colours Brewster saw. Inserting quarter-wave plates (a circular polariscope) removes the \(\varphi\)-dependence, leaving \(I=I_0\sin^2(\delta/2)\).

Exercise 7.1Derive \(I=I_0\sin^22\varphi\sin^2(\delta/2)\) using Jones vectors.

Show solution
Take the polarizer along \(x\), input \((1,0)\). In the principal frame the components are \((\cos\varphi,-\sin\varphi)\). The plate multiplies them by \(1\) and \(e^{i\delta}\). Back in the lab frame the \(y\)-component (analyzer) is \(\sin\varphi\cos\varphi-\cos\varphi\sin\varphi\,e^{i\delta}=\tfrac12\sin2\varphi(1-e^{i\delta})\). Its squared modulus is \(\tfrac14\sin^22\varphi\cdot4\sin^2(\delta/2)\).

Exercise 7.2For glass with \(C=2.7\) brewsters, \(t=1\ \mathrm{cm}\) and \(\lambda=550\ \mathrm{nm}\), what stress difference produces the first dark isochromatic fringe (\(N=1\))?

Show solution
\(N=tC(\sigma_1-\sigma_2)/\lambda=1\) gives \(\sigma_1-\sigma_2=\lambda/(tC)=5.5\times10^{-7}/(0.01\times2.7\times10^{-12})\approx2.0\times10^{7}\ \mathrm{Pa}\), about 20 MPa.

Exercise 7.3A rectangular glass bar is bent by end couples. Where in its cross-section does no fringe appear, and how are the fringes arranged?

Show solution
In pure bending \(\sigma_{xx}\) varies linearly through the depth and other stresses vanish, so \(\sigma_1-\sigma_2=|\sigma_{xx}|\). The neutral axis is dark; fringes of increasing order lie parallel to it, equally spaced, toward the top and bottom faces. This is essentially the strained-glass pattern Brewster described.
Lesson 08

The kaleidoscope

For the general reader. Two mirrors set at an angle produce many images of an object between them. Brewster worked out when these images join into a perfect, seamless symmetric pattern, and named his instrument from Greek words for beautiful form and viewing. Mathematically, a kaleidoscope is a picture of a reflection group.

Goals
  • Show that two reflections compose to a rotation.
  • Derive the condition that the mirror angle be \(\pi/n\).
  • Classify three-mirror kaleidoscopes that tile the plane.
Proposition

Let \(\rho_1,\rho_2\) be reflections of the plane in lines through the origin meeting at angle \(\theta\). Then \(\rho_2\rho_1\) is the rotation by \(2\theta\). If \(\theta=\pi/n\), the group generated by \(\rho_1,\rho_2\) is the dihedral group of order \(2n\), and its images of the wedge between the mirrors tile the full turn exactly once.

Proof. In complex notation, reflection in the line at angle \(a\) is \(z\mapsto e^{2ia}\bar z\). Composing reflections at \(0\) and \(\theta\): \(z\mapsto\bar z\mapsto e^{2i\theta}z\), a rotation by \(2\theta\). If \(\theta=\pi/n\) the rotation has order \(n\), and with one reflection generates a group of \(2n\) elements; the \(2n\) images of the wedge of angle \(\pi/n\) fill \(2\pi\). ∎

Why must the angle divide \(180^\circ\) and not merely \(360^\circ\)? If \(\theta=2\pi/m\) with \(m\) odd, the rotation \(\rho_2\rho_1\) by \(4\pi/m\) has order \(m\), so the group has \(2m\) elements, but \(2m\) wedges of angle \(2\pi/m\) cover the turn twice. The images overlap inconsistently and an asymmetric object shows a seam. Brewster’s patent named \(18^\circ,20^\circ\) and \(22\tfrac12^\circ\), that is \(\pi/10,\pi/9,\pi/8\).

Three-mirror kaleidoscopes

Three mirrors forming a triangular tube give a pattern filling the plane exactly when the triangle has angles \(\pi/p,\pi/q,\pi/r\) with \(\tfrac1p+\tfrac1q+\tfrac1r=1\). The only solutions are \((3,3,3),\ (2,4,4),\ (2,3,6)\).

Exercise 8.1How many images of an object (counting the object itself) does a kaleidoscope with mirrors at \(30^\circ\) show? What is the symmetry group?

Show solution
\(30^\circ=\pi/6\), so \(n=6\): 12 copies in all (the object and 11 images), with symmetry group the dihedral group of order 12.

Exercise 8.2Find all integer solutions of \(\tfrac1p+\tfrac1q+\tfrac1r=1\) with \(2\le p\le q\le r\).

Show solution
Since \(1/p\ge1/3\), \(p\in\{2,3\}\). If \(p=3\) then \(q=r=3\). If \(p=2\) then \(\tfrac1q+\tfrac1r=\tfrac12\) with \(q\le r\), so \(q\in\{3,4\}\): \((2,3,6)\) and \((2,4,4)\). These are the equilateral, right isosceles and 30-60-90 triangles.
Lesson 09

The stereoscope and binocular depth

For the general reader. Each eye sees the world from a slightly different place, and the brain turns the difference into depth. Charles Wheatstone demonstrated this in 1838 with a mirror stereoscope. In 1849 Brewster replaced the mirrors with lenses, producing a small hand-held viewer that, with the new photography, became one of the most popular optical devices of the century.

Goals
  • Relate binocular disparity to depth.
  • Estimate the range of stereoscopic vision.
  • Understand how a lens viewer presents two pictures to the eyes.
Binocular disparity

For eyes separated by baseline \(b\) fixating a point at distance \(Z\), a second point at distance \(Z+\Delta Z\) on the same line of sight produces an angular disparity

\[ \eta\approx\frac{b\,\Delta Z}{Z^2}\qquad(\Delta Z\ll Z,\ b\ll Z). \]

The convergence angle for distance \(Z\) is \(\gamma=2\arctan(b/2Z)\approx b/Z\). Differentiating, \(|d\gamma/dZ|\approx b/Z^2\), which is the formula. Depth resolution falls as \(1/Z^2\), so stereo vision matters most within a few tens of metres.

Brewster’s design

A stereo card carries two photographs taken from viewpoints a few centimetres apart. Brewster’s viewer places a convex half-lens before each eye. Each half-lens magnifies its picture and, because it is the off-centre part of a lens, also deflects light like a weak prism, so the eyes can fuse the two magnified images without strain. No instrument maker in Britain would take up the design, so he had it made in Paris by Jules Duboscq. Shown at the Great Exhibition of 1851, it caught the attention of Queen Victoria, and stereoscopes were soon sold by the hundred thousand. Brewster then disputed Wheatstone’s priority bitterly, crediting the principle to an Edinburgh teacher named Elliot.

Exercise 9.1Take \(b=65\ \mathrm{mm}\) and a best stereo acuity of 20 arcseconds. Beyond what distance can the eye no longer tell an object from the far background by disparity alone?

Show solution
An object at \(Z\) against a background at infinity has disparity \(\approx b/Z\). Setting \(b/Z=20''\approx9.7\times10^{-5}\) rad gives \(Z\approx0.065/9.7\times10^{-5}\approx670\ \mathrm{m}\).

Exercise 9.2A stereo photographer uses a baseline of 65 mm for a scene 3 m away. To make a distant mountain range 5 km away look as deep as that scene, how large a baseline is needed?

Show solution
Relative depths scale as \(b/Z\), so keep \(b/Z\) fixed: \(b=0.065\times5000/3\approx108\ \mathrm{m}\). Wide-baseline “hyperstereo” is used for landscapes and aerial survey.
Lesson 10

Zoned lenses and absorption lines

For the general reader. A lens big enough to send a lighthouse beam far out to sea would be impossibly thick and heavy if made in one piece. Brewster proposed in 1811 to build it from separate rings of glass, each bending light like a prism. Fresnel independently designed and built such lenses in France. Brewster also studied how gases and crystals absorb particular colours, an early step toward spectroscopy.

Goals
  • Design the prism angle of a lens zone.
  • State the Beer–Lambert law of absorption.
  • Place Brewster’s observations of absorption lines in the history of spectroscopy.

Built-up lenses

A lens collimates light from a source at its focus. A ray leaving the focus at height \(h\) on a lens of focal length \(f\) must be turned through an angle \(\arctan(h/f)\). The middle of a plano-convex lens does this with gently curved glass; the outer parts need steep surfaces and great thickness. A zoned lens replaces each annulus by a thin ring whose surface has the right slope, keeping the deviation and discarding the bulk. Georges-Louis Leclerc de Buffon had proposed a stepped burning glass in one piece in 1748; Brewster in 1811 proposed building the zones separately. Fresnel’s lens, built from separate prisms, was first lit at the Cordouan lighthouse in 1823. Brewster pressed British lighthouse authorities to adopt such lenses from 1820 and later complained that Fresnel received the credit.

Thin-prism deviation

A thin prism of apex angle \(A\) and index \(n\) deviates a ray near minimum deviation by \(\delta\approx(n-1)A\). A lens zone at height \(h\) needs \(\delta=\arctan(h/f)\).

Absorption

Beer–Lambert law

Light of wavelength \(\lambda\) passing a path length \(\ell\) through a medium with absorption coefficient \(\alpha(\lambda)\) is attenuated as \(I=I_0\,e^{-\alpha(\lambda)\ell}\).

In 1818–19 Brewster showed that some crystals absorb light differently according to its polarization and direction, the effect now called pleochroism. In 1833 and 1834 he found that nitrous acid gas (nitrogen dioxide) imprints many dark lines on a spectrum, and that some dark lines in the solar spectrum strengthen as the Sun sinks, so they are produced by the Earth’s atmosphere. In 1860, with the chemist John Hall Gladstone, he published a map of the solar spectrum separating these atmospheric lines from solar ones. Around the same time Gustav Kirchhoff and Robert Bunsen showed that the solar lines identify chemical elements.

Exercise 10.1A lighthouse lens has focal length \(f=0.92\ \mathrm{m}\) and glass of index 1.5. Estimate the thin-prism apex angle needed for a zone at \(h=0.25\ \mathrm{m}\). Why do outer zones need a thick-prism treatment?

Show solution
\(\delta=\arctan(0.25/0.92)\approx15.2^\circ\), so \(A\approx\delta/(n-1)\approx30^\circ\). For outer zones \(\delta\) grows past \(30^\circ\), the thin-prism approximation fails, and refraction alone becomes inefficient; Fresnel and later Alan Stevenson used totally reflecting (catadioptric) prisms there.

Exercise 10.2Why should an atmospheric absorption line deepen as the Sun approaches the horizon? Give the dependence of path length on solar zenith angle \(z\) for a plane-parallel atmosphere.

Show solution
The path through a plane-parallel atmosphere is \(\ell=H\sec z\), so the transmitted fraction is \(e^{-\alpha H\sec z}\), falling sharply near the horizon. Solar lines formed in the Sun’s atmosphere do not depend on \(z\). This was Brewster’s criterion.
Part III · Life and legacy
Lesson 11

Science, church and controversy, 1820–1859

Through the 1820s Brewster edited journals, finished the Encyclopaedia and wrote prolifically. He started the Edinburgh Journal of Science in 1824 and received the Keith Prize of the Royal Society of Edinburgh and, in 1830, the Royal Medal of the Royal Society. He shared with Charles Babbage a conviction that British science was neglected by the state and the universities, and in 1831 he was one of the chief promoters of the British Association for the Advancement of Science, whose first meeting was held at York that September. The same year he was knighted and received the Royal Guelphic Order. His Life of Sir Isaac Newton (1831) and Letters on Natural Magic (1832), addressed to his friend Sir Walter Scott, made him a well-known writer.

In optics he remained apart from the majority. He gave up the particle theory of light but never accepted the wave theory, and he argued in print with its defenders. He also fought priority disputes: with Fresnel’s supporters over lighthouse lenses, and with Wheatstone over the stereoscope. He was a friend and supporter of William Henry Fox Talbot, and in Scotland he encouraged the calotype photography of Robert Adamson and David Octavius Hill.

In 1838 he became Principal of the United College of St Salvator and St Leonard at St Andrews. His reforming energy and temper brought constant conflict with colleagues. In 1843, at the Disruption, he left the established Church of Scotland for the new Free Church, which made his position at St Andrews contentious. His wife Juliet died in 1850. In 1854 he published More Worlds than One, a reply to William Whewell defending the view that other planets are inhabited. His enlarged Memoirs of Newton (1855) drew on unpublished papers and remained the standard biography for a century.

DiscussionBrewster discovered laws that the wave theory explained, yet never accepted it. Using Lessons 04 and 06, discuss what an empirical law gains and loses compared with a theory, and why a skilled experimenter might reasonably distrust a new theory in 1830.

Lesson 12

Edinburgh, death, legacy, 1859–1868

In 1857, aged 75, Brewster married Jane Kirk Purnell in Nice. In 1859 he became Principal of the University of Edinburgh, where he had studied as a boy. In 1860 he published with John Hall Gladstone the map of the solar spectrum described in Lesson 10, and in 1864 he became President of the Royal Society of Edinburgh. He also wrote critically of Charles Darwin’s theory. He died of pneumonia on 10 February 1868 at Allerly, his house at Gattonside near Melrose, aged 86, and was buried in the grounds of Melrose Abbey.

Legacy

  • Optics: Brewster’s angle and Brewster windows; the optical classification of crystals into isotropic, uniaxial and biaxial; pleochroism.
  • Engineering: photoelasticity, used for stress analysis in models and for checking residual stress in glass; the unit of the stress-optic coefficient is named the brewster.
  • Instruments: the kaleidoscope and the lenticular stereoscope; advocacy of built-up lenses for lighthouses.
  • Institutions: the British Association; leadership of the universities of St Andrews and Edinburgh and of the Royal Society of Edinburgh.
  • Honours: the Copley (1815), Rumford (1818) and Royal (1830) medals; foreign associate of the Institut de France (1849); the Prussian order Pour le Mérite (1847); officer of the Légion d’honneur (1855).

Final projectBuild or simulate a simple polariscope: two polarizing filters and a strained plastic object (a ruler, a cutlery handle, a bent strip). Photograph the fringes, identify isochromatics and isoclinics using Lesson 07, and estimate the stress difference at one point given a stated \(C\) for the plastic.

Reference

Connections

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Influenced by

Influenced

Colleagues and collaborators

Rivals

Friends

Also mentioned in this life

Fields

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Reference

Sources and further reading

Biography

  1. David Brewster, Wikipedia.
  2. David Brewster, German Wikipedia (RSE offices and medals).
  3. J. J. O’Connor and E. F. Robertson, Sir David Brewster, MacTutor History of Mathematics.
  4. M. M. Gordon, The Home Life of Sir David Brewster, Edinburgh, 1869.
  5. A. D. Morrison-Low and J. R. R. Christie (eds.), “Martyr of Science”: Sir David Brewster 1781–1868, Royal Scottish Museum, 1984.

Physics

  1. D. Brewster, On the laws which regulate the polarisation of light by reflexion from transparent bodies, Phil. Trans. R. Soc. 105 (1815).
  2. D. Brewster, On the laws which regulate the absorption of polarised light by doubly refracting crystals, Phil. Trans. R. Soc. 109 (1819).
  3. D. Brewster, A Treatise on the Kaleidoscope, Edinburgh, 1819.
  4. D. Brewster, The Stereoscope: Its History, Theory, and Construction, London, 1856.
  5. D. Brewster and J. H. Gladstone, On the lines of the solar spectrum, Phil. Trans. R. Soc. 150 (1860).
  6. M. Born and E. Wolf, Principles of Optics, Cambridge University Press (Fresnel equations; crystal optics).
  7. E. Hecht, Optics, Pearson (Brewster’s angle, piles of plates, photoelasticity).
  8. Photoelasticity, Kaleidoscope, Stereoscope, Fresnel lens, Wikipedia.
  9. H. S. M. Coxeter, Regular Polytopes, Dover (kaleidoscopes and reflection groups).