Connection I — Diffeomorphism Gauging: DeTurck ↔ BMS
1. DeTurck Vector Field and Strict Parabolicity
Hamilton’s Ricci flow $\partial_t g_{ij} = -2R_{ij}$ is only weakly parabolic: the principal symbol of $-2R_{ij}$ viewed as a second-order operator on $g_{ij}$ has a kernel spanned by pure gauge modes (infinitesimal diffeomorphisms). To see this, linearise $R_{ij}$ around a background $\bar{g}$ with $g_{ij} = \bar{g}_{ij} + h_{ij}$:
$$-2\,\delta R_{ij} = -\bar{\nabla}^2 h_{ij} + \bar{\nabla}_i V_j + \bar{\nabla}_j V_i + \text{lower order}$$
where $V_j = \bar{\nabla}^k h_{jk} - \frac{1}{2}\bar{\nabla}_j h^k{}_k$. The principal symbol in Fourier space ($\bar{\nabla} \to i\xi$) is:
$$\sigma(\xi)_{ij,kl}\,h^{kl} = |\xi|^2 h_{ij} - \xi_i\xi^k h_{jk} - \xi_j\xi^k h_{ik} + \cdots$$
For gauge modes $h_{ij} = \nabla_i v_j + \nabla_j v_i$, we have $\sigma(\xi)\,h = 0$, confirming the kernel. DeTurck’s trick introduces a background metric $\hat{g}$ and defines:
$$\boxed{W^k = g^{pq}\!\left(\Gamma^k_{pq} - \hat{\Gamma}^k_{pq}\right)}$$
The Ricci-DeTurck flow is $\partial_t g_{ij} = -2R_{ij} + \mathcal{L}_W g_{ij}$. The Lie derivative contributes to the principal symbol:
$$\mathcal{L}_W g_{ij}\Big|_{\rm principal} = \nabla_i W_j + \nabla_j W_i \sim \nabla_i g^{pq}\nabla_p h_{qj} + \cdots$$
This exactly cancels the degenerate directions. The full principal symbol of the Ricci-DeTurck operator becomes:
$$\sigma_{\rm RDT}(\xi)_{ij,kl}\,h^{kl} = |\xi|^2\,h_{ij}$$
This is the symbol of the scalar Laplacian acting on each component of $h_{ij}$ independently — manifestly strictly parabolic. Standard PDE theory (Schauder estimates) then guarantees short-time existence and uniqueness.
2. BRST Complex for DeTurck
The gauge redundancy of Ricci flow under $\mathrm{Diff}(M)$ is encoded in a BRST complex. Introduce a Grassmann-odd ghost field $c^i$ with ghost number 1. The BRST operator $s_{\rm DT}$ acts as:
$$s_{\rm DT}\,g_{ij} = \mathcal{L}_c\,g_{ij} = \nabla_i c_j + \nabla_j c_i$$
$$s_{\rm DT}\,c^i = c^j\partial_j c^i$$
Proof of nilpotency $s_{\rm DT}^2 = 0$: Compute $s_{\rm DT}^2 g_{ij}$:
$$s_{\rm DT}^2 g_{ij} = s_{\rm DT}(\nabla_ic_j + \nabla_jc_i) = \mathcal{L}_{s(c)}g_{ij} + \mathcal{L}_c(\mathcal{L}_c g_{ij})$$
Using $s_{\rm DT} c^i = c^j\partial_j c^i = \frac{1}{2}[c,c]^i_{\rm Lie}$ and the identity $\mathcal{L}_{[c,c]} = 2\mathcal{L}_c\mathcal{L}_c$ for Grassmann-odd parameters (where the factor of 2 accounts for the anticommutation), we get:
$$s_{\rm DT}^2 g_{ij} = \mathcal{L}_{\frac{1}{2}[c,c]}g_{ij} - \frac{1}{2}\mathcal{L}_{[c,c]}g_{ij} = 0$$
The DeTurck vector $W^k$ serves as the gauge-fixing fermion: $\mathcal{L}_W g_{ij} = s_{\rm DT}\,\psi_{ij}$ for an appropriate anti-ghost $\psi$, ensuring the gauge-fixed action remains in the same BRST cohomology class.
3. BRST Complex for BMS
On $\mathscr{I}^+$, the BMS ghosts are $(c^A, c_f)$ corresponding to superrotations and supertranslations. The BRST transformation of the asymptotic shear is:
$$s_{\rm BMS}\,C_{AB} = \mathcal{L}_{c^A}C_{AB} + 2D_{\langle A}D_{B\rangle}c_f + \frac{u}{2}(D_Cc^C)\,N_{AB}$$
The ghost self-interactions encoding the BMS algebra are:
$$s_{\rm BMS}\,c^A = c^B\partial_B c^A, \qquad s_{\rm BMS}\,c_f = c^A\partial_A c_f - \frac{1}{2}(D_Ac^A)\,c_f$$
Nilpotency check: For $s_{\rm BMS}^2 C_{AB}$, the supertranslation part gives $2D_{\langle A}D_{B\rangle}(s_{\rm BMS}\,c_f)$. Substituting $s_{\rm BMS}c_f = c^A\partial_Ac_f - \frac{1}{2}(D_Ac^A)c_f$ and combining with $s_{\rm BMS}(\mathcal{L}_{c^A}C_{AB}) = \mathcal{L}_{[c,c]}C_{AB} + 2D_{\langle A}D_{B\rangle}(\mathcal{L}_c c_f)$, all terms cancel by the BMS algebra relations, confirming $s_{\rm BMS}^2 = 0$.
4. Physical Observables as BRST Cohomology
DeTurck side: Perelman’s $\mathcal{W}$-entropy is $s_{\rm DT}$-closed. Under an infinitesimal diffeomorphism generated by $c^i$:
$$s_{\rm DT}\,\mathcal{W}[g,f,\tau] = \int_M \frac{\delta\mathcal{W}}{\delta g_{ij}}\left(\nabla_ic_j + \nabla_jc_i\right)e^{-f}\,d\mu = 0$$
The vanishing follows because $\mathcal{W}$ is diffeomorphism-invariant by construction (the integrand transforms as a scalar density). Moreover, $\mathcal{W}$ is not $s_{\rm DT}$-exact (it is not purely gauge), so $[\mathcal{W}] \in H^0(s_{\rm DT})$.
BMS side: The spin memory $\Delta\Psi$ is $s_{\rm BMS}$-closed. Under a supertranslation, $C_{AB} \to C_{AB} + 2D_{\langle A}D_{B\rangle}c_f$. The B-mode part of this shift is:
$$\delta\Psi = \epsilon^{AB}D_A D_B c_f = 0$$
since $\epsilon^{AB}D_AD_B$ acting on a scalar vanishes identically (antisymmetric derivatives on a scalar commute on $S^2$ up to curvature, which is pure trace). Therefore $\Delta\Psi$ is gauge-invariant: $[\Delta\Psi] \in H^0(s_{\rm BMS})$.
5. Riemannian Moduli Space and the Slice Theorem
The space of Riemannian metrics on a closed manifold $M$ is an infinite-dimensional Frechet manifold:
$$\mathrm{Met}(M) = \{g \in \Gamma(S^2T^*M) : g > 0\}$$
The diffeomorphism group $\mathrm{Diff}(M)$ acts by pullback: $\phi \cdot g = \phi^*g$. The moduli space $\mathcal{M} = \mathrm{Met}(M)/\mathrm{Diff}(M)$ is the orbit space. The slice theorem (Ebin 1970) states that at each $g \in \mathrm{Met}(M)$, there exists a local slice $\mathcal{S}_g$ transverse to the orbit:
$$T_g\mathrm{Met}(M) = T_g(\mathrm{Diff}(M)\cdot g) \oplus T_g\mathcal{S}_g$$
The orbit tangent space is $T_g(\mathrm{Diff}\cdot g) = \{\mathcal{L}_X g : X \in \mathfrak{X}(M)\} = \mathrm{Im}(\delta^*_g)$ where $(\delta^*_g X)_{ij} = \nabla_iX_j + \nabla_jX_i$. The slice is the $L^2$-orthogonal complement:
$$\mathcal{S}_g = \ker(\delta_g) = \{h_{ij} : \nabla^i h_{ij} - \frac{1}{2}\nabla_j h^k{}_k = 0\}$$
This is exactly the de Donder (harmonic) gauge condition. The DeTurck vector field $W^k$ projects the Ricci flow trajectory onto this slice, ensuring the flow remains transverse to diffeomorphism orbits.
6. BMS Phase Space as Symplectic Reduction
The gravitational phase space at $\mathscr{I}^+$ starts from the extended space of radiative data:
$$\widetilde{\mathcal{P}} = \{(C_{AB}(u,x^C),\, N_A(u,x^B),\, m_B(u,x^A))\}$$
equipped with the Ashtekar-Streubel symplectic form:
$$\Omega = \frac{1}{16\pi G}\int_{\mathscr{I}^+}du\oint_{S^2}\delta N_{AB} \wedge \delta C^{AB}\,d^2\Omega$$
The trivial diffeomorphisms $\mathrm{Diff}_0$ (those that vanish at $\mathscr{I}^+$) generate Hamiltonian flows with moment map $\mu = 0$ (constraints). Symplectic reduction gives the physical phase space:
$$\boxed{\mathcal{P}_{\rm grav} = \mu^{-1}(0)\,/\,\mathrm{Diff}_0 = \widetilde{\mathcal{P}}\,/\!/\,\mathrm{Diff}_0}$$
The BMS group acts as the residual symmetry on $\mathcal{P}_{\rm grav}$, analogous to how global isometries act on the Riemannian moduli space after DeTurck gauge-fixing. The structural parallel is: DeTurck quotients by $\mathrm{Diff}(M)$ to get $\mathcal{M}$, while the BMS programme quotients by $\mathrm{Diff}_0$ to get $\mathcal{P}_{\rm grav}$.
Simulation: DeTurck Flow vs Ricci Flow on a Deformed Sphere
We simulate the 2D Ricci flow on an axially symmetric deformed sphere, comparing the pure Ricci flow (weakly parabolic, gauge modes present) with the Ricci-DeTurck flow (strictly parabolic, gauge-fixed). The DeTurck vector field $W^k$ corrects the gauge drift and ensures smooth convergence to the round metric.
DeTurck Flow vs Ricci Flow: Convergence to Round Sphere
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