courseshub.world · Lives in Mathematics and Physics

François Arago

Dominique François Jean Arago

A course in two strands: the adventurous life of the Catalan astronomer who measured the meridian, ran French science for a generation and abolished slavery in the colonies, and the experiments in light and magnetism that made the wave theory and the age of induction possible.

Born 26 February 1786, Estagel Died 2 October 1853, Paris Copley Medal Royal Society, 1825 Level advanced undergraduate → graduate
Arago’s 1838 test, done by Foucault and by Fizeau and Breguet in 1850. The mirror turns while light makes the round trip; the image returning through water is displaced more, so light is slower in water.
Lesson 00

How to use this course

François Arago is less known today than the people whose work he made possible. He saw the bright spot that won the wave theory of light its decisive victory. He reported Ørsted’s discovery to Paris and set Ampère to work. He found the magnetic drag of a spinning copper disc that Faraday later explained by induction. He designed the experiment that decided whether light is slower in water. He also founded the Comptes rendus, launched photography as a public invention and, as a minister in 1848, ended slavery in the French colonies. This course follows the physics in detail and places it in one of the most eventful lives in the history of science.

Prerequisites for Part II
  • Wave optics: interference, polarization, Malus’s law, refractive index.
  • Introductory electromagnetism: the magnetic field of a current, Faraday’s law, Ohm’s law.
  • For Lesson 04, a little differential geometry of the ellipse; for Lesson 08, the dipole picture of scattering.

Each technical lesson opens with a paragraph for the general reader, then gives precise statements, derivations and exercises with folded solutions. Arago was above all an experimenter; the lessons give the theory that explains his observations, mostly in the form it took later, and say where his own interpretation differed.

Reference

Timeline

1786Born 26 February at Estagel, Roussillon, eldest son of François Bonaventure Arago.
1803Enters the École polytechnique after examination at Toulouse.
1805On Poisson’s recommendation, secretary at the Paris Observatory, and chosen to complete the meridian survey.
18063 September: leaves Paris for Spain with Jean-Baptiste Biot.
1808Imprisoned on Mallorca as a suspected spy; escapes to Algiers; captured at sea and held at Roses and Palamós.
1809Reaches Marseille on 2 July. Elected to the Académie des sciences on 18 September, aged 23. Teaches analytic geometry at the École polytechnique in place of Monge.
181010 December: reports that the refraction of starlight does not depend on the Earth’s motion.
1811Colours of polarized light in thin crystals; rotation of the plane of polarization in quartz. Marries Lucie Carrier-Bescombes.
1815Meets Augustin Fresnel and becomes his patron.
1816With Fresnel, finds that perpendicularly polarized beams do not interfere. Co-editor, with Gay-Lussac, of the Annales de chimie et de physique.
1818Fellow of the Royal Society of London.
1819Observes the bright spot predicted by Poisson; Fresnel wins the Grand Prix.
1820September: reports Ørsted’s experiment to the Académie, then magnetizes iron and steel with currents, with Ampère.
1822Full member of the Bureau des longitudes.
182422 November: first account of magnetism of rotation.
1825Copley Medal of the Royal Society.
18307 June: perpetual secretary of the Académie des sciences, succeeding Fourier.
1831Deputy for the Pyrénées-Orientales.
1835Founds the weekly Comptes rendus of the Académie.
1838Proposes the rotating-mirror comparison of the speed of light in air and water.
1839Presents Daguerre’s process; on 19 August describes it to a joint session of the Academies of Sciences and Fine Arts.
1843Director of the Paris Observatory after Alexis Bouvard’s death.
1846Neptune is found at the position computed by his protégé Urbain Le Verrier.
1848Minister of the Navy and Colonies, then also of War, in the Provisional Government; decree of 27 April abolishing slavery. President of the Executive Commission, May–June.
1850Foucault, and Fizeau with Breguet, show light is slower in water. Rumford Medal.
1852Refuses the oath of allegiance to Louis-Napoléon; the government keeps him at the Observatory.
1853Dies in Paris on 2 October, aged 67. Buried in Père Lachaise.
Part I · Formation
Lesson 01

Estagel, Perpignan, Polytechnique, 1786–1805

Dominique François Jean Arago was born on 26 February 1786 at Estagel, a Catalan-speaking village in Roussillon, near the Spanish border. His father, François Bonaventure Arago, was mayor of the village and later treasurer of the Mint at Perpignan. François was the eldest of several brothers, most of whom led adventurous lives: Jacques sailed around the world with Louis de Freycinet and became a writer, Étienne a playwright, and Jean a general in the Mexican army.

He was schooled at the municipal college of Perpignan, where he discovered a love of mathematics, and prepared largely on his own for the entrance examination of the École polytechnique. Examined at Toulouse in 1803, he was placed among the top entrants and entered the school late that year.

At Polytechnique he became friends with Siméon Denis Poisson, a young teacher only five years older. Poisson recognized his talent. When Laplace asked for someone to finish the measurement of the Paris meridian, left incomplete by Pierre Méchain’s death in Spain in 1804, Poisson proposed Arago. In 1805 he was given a post as secretary at the Paris Observatory and nominated for the survey. He was nineteen.

Lesson 02

The meridian and captivity, 1806–1809

The metre had been defined in 1791 as one ten-millionth of the distance from the North Pole to the equator along the meridian of Paris. Jean-Baptiste Delambre and Pierre Méchain had measured the arc from Dunkirk to Barcelona between 1792 and 1798. The plan now was to carry the triangulation south across the sea to the Balearic Islands, so that the arc would straddle the 45th parallel more symmetrically. Arago and Jean-Baptiste Biot left Paris on 3 September 1806. They spent months on mountaintops in Valencia and the islands, signalling at night with fires and lamps across long stretches of sea. Biot returned to Paris after they had fixed the latitude of Formentera; Arago stayed to complete the measurements.

Three captures

In May 1808 Napoleon placed his brother Joseph on the Spanish throne, and Spain rose against the French. On Mallorca, Arago’s fires on the summit of Mount Galatzó made the islanders suspect a French spy. He surrendered and was imprisoned in the castle of Bellver in June 1808. At the end of July he escaped in a fishing boat to Algiers, which he reached on 3 August. Sailing for Marseille on 16 August, his ship was captured by a Spanish corsair within sight of the French coast, and he was held at Roses and Palamós until late November. Released, he sailed again, but a storm drove the ship to Bougie on the North African coast. He walked back to Algiers, arriving on 25 December, and was again held captive there until the French consul obtained his release.

He sailed at last on 21 June 1809 and landed at Marseille on 2 July, carrying his survey notebooks. In quarantine he received a letter from Alexander von Humboldt, the start of a friendship that lasted more than forty years. His adventures made him famous in Paris before he had published a scientific paper of note.

Lesson 03

Academician at twenty-three, 1809–1820

On 18 September 1809, at twenty-three, Arago was elected to the Académie des sciences. In the same year Gaspard Monge chose him to teach analytic geometry at the École polytechnique; he taught there until 1830. He was named an astronomer at the Observatory, where he lived for the rest of his life. In 1811 he married Lucie Carrier-Bescombes; they had sons. From the early 1810s until 1845 he gave public lectures on astronomy at the Observatory, famous for their clarity, which became his posthumous Astronomie populaire.

His research of the decade was in optics. He belonged to the circle of young scientists around Laplace and Claude-Louis Berthollet at Arcueil, where light was understood as a stream of particles. In 1810 he tested that theory with starlight (Lesson 05). In 1811 he discovered the colours of polarized light passing through thin crystal plates and the rotation of the plane of polarization in quartz (Lesson 06). Biot took up both subjects with energy and published extensive particle-based theories of them, and the two former companions became lasting rivals.

In 1815 Arago met Augustin Fresnel, a young engineer with a theory of diffraction based on waves. Arago became his advocate, his collaborator and his link to the Académie. From 1816 he and Joseph Louis Gay-Lussac edited the Annales de chimie et de physique, one of the leading physics journals of the century. The Royal Society of London elected him a fellow in 1818.

Part II · The physics
Lesson 04

Measuring the Earth

For the general reader. To define the metre as a fraction of the Earth, surveyors had to measure a long arc of a meridian and the latitudes at its ends. Because the Earth is flattened at the poles, a degree of latitude is slightly longer in the north than in the south. Arago’s extension of the arc to the Balearics, and his later pendulum measurements of gravity with Biot, fed into the shape of the Earth and the length of the metre.

Goals
  • Compute the length of a degree of latitude on an ellipsoid.
  • Derive the flattening from two arc measurements.
  • Relate the seconds pendulum to the variation of gravity with latitude.

Meridian arcs

Model the Earth as an ellipsoid of revolution with equatorial radius \(a\) and eccentricity \(e\), where \(e^2=2f-f^2\) and \(f=(a-b)/a\) is the flattening. Latitude \(\varphi\) is the angle between the local vertical (the plumb line) and the equatorial plane; it is what astronomers measure from star altitudes.

Proposition (meridian radius of curvature)

The radius of curvature of the meridian ellipse at geodetic latitude \(\varphi\) is

\[ M(\varphi)=\frac{a(1-e^2)}{(1-e^2\sin^2\varphi)^{3/2}}, \]

so the length of one degree of latitude is \(\frac{\pi}{180}M(\varphi)\), and to first order in \(f\), \(M(\varphi)\approx a\big(1-2f+3f\sin^2\varphi\big)\).

Derivation. Parametrize the meridian ellipse \(x^2/a^2+z^2/b^2=1\) by the normal angle \(\varphi\). The normal is parallel to \((x/a^2,z/b^2)\), so \(\tan\varphi=\frac{a^2z}{b^2x}\). Solving gives \(x=\frac{a\cos\varphi}{W}\) and \(z=\frac{a(1-e^2)\sin\varphi}{W}\) with \(W=\sqrt{1-e^2\sin^2\varphi}\). The arc element satisfies \(ds=M\,d\varphi\), and differentiating, \(\big|\frac{d}{d\varphi}(x,z)\big|=\frac{a(1-e^2)}{W^3}\). Expanding \((1-e^2)\approx1-2f\) and \(W^{-3}\approx1+3f\sin^2\varphi\) gives the first-order form.

Gravity and the pendulum

On a rotating, flattened Earth, gravity increases from equator to pole. Alexis Clairaut’s theorem of 1743 links the increase to the flattening:

\[ g(\varphi)\approx g_e\Big(1+\big(\tfrac52 m-f\big)\sin^2\varphi\Big),\qquad m=\frac{\omega^2a^3}{GM}\approx\frac{1}{289}. \]

A pendulum of length \(L\) beating seconds (half-period one second) satisfies \(\pi\sqrt{L/g}=1\ \mathrm s\), so \(L=g/\pi^2\). Measuring the seconds-pendulum length at many latitudes, as Biot and Arago did along the meridian and as far north as Leith and the Shetland Islands, gives \(g(\varphi)\), and through Clairaut’s theorem an independent estimate of \(f\).

Exercise 4.1A degree of latitude measures 111.035 km at \(\varphi=40^\circ\) and 111.229 km at \(\varphi=50^\circ\). Use the first-order formula to estimate the flattening \(f\).

Show solution
The ratio is \(\frac{1-2f+3f\sin^2 50^\circ}{1-2f+3f\sin^2 40^\circ}\approx1+3f(\sin^2 50^\circ-\sin^2 40^\circ)=1+3f\cos 80^\circ\). So \(3f(0.1736)\approx\frac{0.194}{111.035}=1.75\times10^{-3}\), and \(f\approx3.35\times10^{-3}\approx1/298\). An error of only 30 m in either degree would change \(f\) by about 15%, which is why surveyors wanted arcs as long as possible.

Exercise 4.2With \(f=1/298\) and \(m=1/289\), how much longer is a seconds pendulum at the pole than at the equator, if \(g_e=9.780\ \mathrm{m\,s^{-2}}\)?

Show solution
\(\tfrac52m-f=0.00865-0.00336=0.00529\). So \(g_p\approx9.780\times1.00529\approx9.832\ \mathrm{m\,s^{-2}}\). Then \(L_p-L_e=(g_p-g_e)/\pi^2\approx0.0517/9.870\approx5.2\ \mathrm{mm}\), on a length of about 991 mm.

Exercise 4.3Show that the meridian quadrant of an ellipsoid is \(Q\approx\frac{\pi}{2}a\big(1-\tfrac f2\big)\) to first order in \(f\). With \(a=6378.137\) km and \(f=1/298.257\), compare \(Q\) with \(10^7\) m.

Show solution
Using \(M\approx a(1-2f+3f\sin^2\varphi)\) and \(\int_0^{\pi/2}\sin^2\varphi\,d\varphi=\pi/4\), \(Q=\int_0^{\pi/2}M\,d\varphi\approx a\big(\tfrac{\pi}{2}(1-2f)+\tfrac{3\pi}{4}f\big)=\tfrac{\pi}{2}a\big(1-\tfrac f2\big)\). Numerically \(10018.75\times0.99832\approx10002.0\) km. The quadrant is about \(1.0002\times10^7\) of today’s metres, so the metre fixed in 1799 is short of its intended definition by about 0.2 mm.
Lesson 05

Starlight through a prism, 1810

For the general reader. If light is a hail of particles, starlight should arrive at slightly different speeds depending on whether the Earth is moving toward the star or away from it, and a prism should bend the two kinds of light differently. Arago looked for the effect in 1810 and found nothing. The null result was the first of a line of experiments on light and motion that ended with Einstein’s relativity.

Goals
  • Compute the aberration of starlight and the expected size of Arago’s effect.
  • State Fresnel’s partial drag coefficient and show how it explains the null result.
  • Connect the drag coefficient to the relativistic addition of velocities.

Aberration

The Earth’s orbital speed is \(v\approx30\ \mathrm{km\,s^{-1}}\), so \(v/c\approx10^{-4}\). James Bradley’s aberration of 1729 shifts the apparent direction of a star by up to \(v/c\) radians, about 20.5 arcseconds. In the particle theory, refraction occurs because a medium attracts the particles and speeds them up, and the deviation by a prism depends on the speed of the incident particles. Arago placed a prism in front of his telescope and compared the deviation of starlight at times when the Earth moved toward the star and away from it. The particle theory predicted a change of relative order \(v/c\) in the deviation, which he expected to detect. He saw no difference, and proposed that the eye might respond only to particles of a single speed.

Fresnel’s drag coefficient (1818)

If a transparent body of refractive index \(n\) moves through the aether with velocity \(v\), the light inside it moves, relative to the aether, with velocity

\[ u=\frac{c}{n}+\Big(1-\frac1{n^2}\Big)v \]

along the direction of motion. With this partial drag, the laws of refraction and reflection observed in a moving laboratory are unchanged to first order in \(v/c\).

Fresnel wrote his drag hypothesis in a letter to Arago precisely to explain the 1810 result. Hippolyte Fizeau confirmed the coefficient in moving water in 1851. Einstein’s theory gives it without any aether: the speed of light in the medium’s rest frame is \(c/n\), and relativistic velocity addition gives

\[ u=\frac{c/n+v}{1+v/(nc)}\approx\frac cn+v-\frac{v}{n^2}+O\big(v^2/c\big). \]

Exercise 5.1Compute the constant of aberration in arcseconds from \(v=29.8\ \mathrm{km\,s^{-1}}\).

Show solution
\(v/c=29.8/299792\approx9.94\times10^{-5}\) rad, times \(206265''\) per radian gives about \(20.5''\).

Exercise 5.2In Fizeau’s 1851 experiment water (\(n=1.333\)) flowed at 7 m/s. Find the change in the speed of light in the water predicted by full drag, by Fresnel’s partial drag, and by no drag.

Show solution
Full drag: 7 m/s. Fresnel: \(f=1-1/n^2=1-0.563=0.437\), so about 3.1 m/s. No drag: 0. Fizeau’s interference fringes shifted by an amount matching Fresnel’s value.
Lesson 06

Colours of polarized light and optical rotation

For the general reader. In 1808 Étienne-Louis Malus found that reflected light is polarized. Three years later Arago sent polarized light through a thin sheet of mica and looked at it through a crystal of Iceland spar. Brilliant colours appeared, changing as he turned the crystal. He also found that quartz cut across its axis turns the direction of polarization, by an amount that depends on colour. These two discoveries became tools for mineralogists, chemists and engineers.

Goals
  • State Malus’s law.
  • Derive the intensity transmitted by a birefringent plate between polarizers.
  • Explain optical rotation as circular birefringence.
Malus’s law (1809)

If linearly polarized light of intensity \(I_0\) meets an analyser whose transmission axis makes angle \(\theta\) with the plane of polarization, the transmitted intensity is \(I=I_0\cos^2\theta\).

Chromatic polarization

A thin plate of a birefringent crystal such as mica has two perpendicular axes with indices \(n_1,n_2\). Let polarized light make angle \(\psi\) with axis 1, and let the plate have thickness \(d\). The two components acquire the phase difference \(\delta=2\pi(n_1-n_2)d/\lambda\).

Proposition (plate between polarizers)

With crossed polarizers the transmitted intensity is

\[ I_\perp=I_0\sin^22\psi\,\sin^2\frac\delta2, \]

and with parallel polarizers \(I_\parallel=I_0-I_\perp\). Since \(\delta\) depends on \(\lambda\), the two settings show complementary colours.

Derivation. Take the incident field \(E_0(\cos\psi,\sin\psi)\) in the plate axes. After the plate, up to a common phase, it is \(E_0(\cos\psi,\ \sin\psi\,e^{i\delta})\). The crossed analyser projects on \((-\sin\psi,\cos\psi)\): amplitude \(E_0\sin\psi\cos\psi\,(e^{i\delta}-1)\), whose square modulus is \(E_0^2\tfrac14\sin^22\psi\cdot4\sin^2(\delta/2)\). The parallel case follows from energy conservation in a lossless plate. Arago called the effect depolarization; the explanation by interference is due to Fresnel and Thomas Young.

Optical rotation

A quartz plate cut perpendicular to its optic axis turns the plane of polarization by an angle proportional to its thickness. Biot found that the rotation varies roughly as \(1/\lambda^2\), and that some liquids such as turpentine and sugar solutions do the same. Fresnel explained the effect in 1822 by resolving linear polarization into left and right circular components that travel at slightly different speeds:

\[ \rho=\frac{\pi d}{\lambda}\,(n_L-n_R). \]

Exercise 6.1A mica plate has \(n_1-n_2=0.0050\). What is the thinnest plate that acts as a half-wave plate for \(\lambda=590\) nm, and what does it transmit between crossed polarizers at \(\psi=45^\circ\)?

Show solution
Half-wave means \(\delta=\pi\), so \(d=\lambda/(2\Delta n)=590\times10^{-9}/0.010=59\ \mu\mathrm m\). Then \(I_\perp=I_0\cdot1\cdot1=I_0\): the plate rotates the polarization by \(90^\circ\) for that wavelength. Other wavelengths are partly blocked, so white light emerges coloured.

Exercise 6.2Quartz rotates sodium light (589 nm) by about \(21.7^\circ\) per millimetre. Find \(n_L-n_R\).

Show solution
\(\rho=21.7^\circ=0.379\) rad for \(d=10^{-3}\) m. Then \(n_L-n_R=\rho\lambda/(\pi d)=0.379\cdot589\times10^{-9}/(\pi\times10^{-3})\approx7.1\times10^{-5}\), about one part in 20 000 of the index.

Exercise 6.3A plate with \(\delta\) independent of \(\psi\) is rotated between crossed polarizers. At what angles \(\psi\) does it appear dark for all colours?

Show solution
When \(\sin2\psi=0\), that is \(\psi=0^\circ,90^\circ,180^\circ,270^\circ\): the incident polarization lies along one of the plate’s axes and passes unchanged. These are the extinction positions used to locate crystal axes in a polarizing microscope.
Lesson 07

The Fresnel–Arago laws and the bright spot

For the general reader. Between 1816 and 1819 Arago and Fresnel showed that light polarized in perpendicular planes never interferes. This was the key evidence that light vibrates across its direction of travel, as waves on a rope do, and not along it like sound. In 1819 Arago tested a strange prediction of Fresnel’s theory, that the shadow of a small disc has a bright centre, and found the spot. The two results ended the dominance of the particle theory in France.

Goals
  • State the Fresnel–Arago laws and derive them from transverse vibrations.
  • Prove with Fresnel zones that the centre of a disc’s shadow is bright.
Fresnel–Arago laws (1819)
  1. Two rays polarized in the same plane interfere like ordinary light.
  2. Two rays polarized at right angles do not interfere.
  3. Two rays polarized at right angles, obtained from unpolarized light, do not interfere even when brought to the same plane of polarization.
  4. Two rays polarized at right angles, obtained from the same polarized beam, interfere when brought to the same plane.

If the vibration is a transverse vector, laws 1 and 2 are immediate: \(|\mathbf E_1+\mathbf E_2|^2=|\mathbf E_1|^2+|\mathbf E_2|^2+2\,\mathrm{Re}(\mathbf E_1\cdot\mathbf E_2^*)\), and the cross term vanishes when the vectors are perpendicular. Laws 3 and 4 depend on coherence: the two components of unpolarized light have phases that vary randomly relative to each other, so the cross term averages to zero, while components split from one polarized beam keep a fixed relative phase.

The bright spot

Poisson, a judge of the 1818–19 prize on diffraction, deduced from Fresnel’s memoir that the centre of the shadow of a circular disc should be as bright as if the disc were absent. He regarded this as a refutation. Arago, chairing the commission, made the experiment with a disc about 2 mm across and saw the spot. He noted later that Joseph-Nicolas Delisle and Giacomo Maraldi had seen it in the early eighteenth century.

Proposition (on-axis intensity behind a disc)

For a plane wave of intensity \(I_0\) falling on an opaque disc, the intensity on the axis at any distance large compared with \(\lambda\) is approximately \(I_0\).

Sketch with Fresnel zones. Seen from an axial point \(P\) at distance \(z\), divide the unobstructed wavefront outside the disc into annular zones whose distances from \(P\) increase by \(\lambda/2\). Successive zones contribute amplitudes \(A_1,A_2,\dots\) of alternating sign whose magnitudes decrease slowly. The sum \(A_1-A_2+A_3-\cdots\) is close to \(A_1/2\), half the first unobstructed zone. For a free wave the same argument starting from the centre gives \(A_1^{\text{free}}/2\). When the disc is small, the first zone outside it differs little from the first free zone, so the intensities agree. For larger discs the spot persists, growing narrower and fainter only slowly as the obliquity of the zones increases.

Exercise 7.1For Arago’s disc of radius \(R=1\) mm, \(\lambda=550\) nm and \(z=1\) m, how many Fresnel zones does the disc cover? (The \(m\)-th zone boundary is at radius \(\sqrt{m\lambda z}\).)

Show solution
\(m=R^2/(\lambda z)=10^{-6}/(5.5\times10^{-7})\approx1.8\). The disc covers less than two zones, so the first unobstructed zone is comparable to the first free one and the spot is bright.

Exercise 7.2Two beams of equal intensity \(I\) polarized at \(60^\circ\) to each other, with a fixed phase difference \(\phi\), overlap. Find the fringe visibility \((I_{\max}-I_{\min})/(I_{\max}+I_{\min})\).

Show solution
\(I_{\text{tot}}=2I+2I\cos60^\circ\cos\phi=2I+I\cos\phi\). So \(I_{\max}=3I\), \(I_{\min}=I\), visibility \(1/2=\cos60^\circ\). The visibility falls to zero at \(90^\circ\), the second Fresnel–Arago law.
Lesson 08

The polarized sky, comets and the Sun

For the general reader. Arago was the first to use polarization as a tool of astronomy. He noticed that the blue sky is partly polarized, most strongly about ninety degrees from the Sun, and that there are special points where the polarization vanishes. He found polarization in the light of a comet’s tail, showing it shone partly by reflected sunlight. He argued from the absence of polarization in light from the edge of the Sun that its visible surface is gaseous.

Goals
  • Derive the degree of polarization of single (Rayleigh) scattering.
  • Understand why neutral points require multiple scattering.
  • Follow Arago’s polarimetric argument about the Sun.

Single scattering

A small particle, much smaller than the wavelength, scatters light by oscillating as an induced dipole. A dipole radiates no field along its own axis. Unpolarized sunlight has two independent components perpendicular to its direction; let the scattering angle be \(\Theta\) between the incident and scattered directions. The component perpendicular to the scattering plane radiates fully, the component in the plane radiates with a factor \(\cos^2\Theta\).

Proposition (Rayleigh, 1871)

For single scattering of unpolarized light by particles small compared with the wavelength, the scattered intensity and the degree of linear polarization are

\[ I(\Theta)\propto\frac{1+\cos^2\Theta}{\lambda^4},\qquad P(\Theta)=\frac{1-\cos^2\Theta}{1+\cos^2\Theta}=\frac{\sin^2\Theta}{1+\cos^2\Theta}. \]

Single scattering predicts zero polarization only at \(\Theta=0\) and \(\Theta=180^\circ\), toward the Sun and directly away from it. Observed skies show neutral points displaced from these directions. The Arago point lies about 20° above the antisolar point; Jacques Babinet and David Brewster later found neutral points above and below the Sun. They arise because light scattered more than once adds a component polarized at right angles to the single-scattering pattern.

Comets and the Sun

In 1819 Arago examined the tail of the great comet of that year with his polariscope and found it polarized, so part of its light is reflected sunlight. He also observed that light from the edge of the Sun’s disc is not polarized. Light emitted at a grazing angle from an incandescent solid or liquid surface is polarized, while light from an incandescent gas is not. He concluded that the luminous surface of the Sun is gaseous, a conclusion confirmed in substance by later solar physics.

Exercise 8.1Compute \(P\) at \(\Theta=90^\circ\), \(60^\circ\) and \(30^\circ\). Why is the observed maximum near \(90^\circ\) only about 0.7 or 0.8?

Show solution
\(P(90^\circ)=1\); \(P(60^\circ)=0.75/1.25=0.6\); \(P(30^\circ)=0.25/1.75\approx0.14\). Multiple scattering, reflection from the ground, aerosols larger than the wavelength and the anisotropy of air molecules all reduce the maximum.

Exercise 8.2By what factor is blue light (450 nm) scattered more than red light (700 nm)?

Show solution
\((700/450)^4\approx(1.556)^4\approx5.9\). This is why the clear sky is blue and the setting Sun red.
Lesson 09

The electromagnet and magnetism of rotation

For the general reader. In September 1820 Arago brought news of Ørsted’s experiment to Paris. Within days he showed that a current-carrying wire picks up iron filings like a magnet, and with Ampère he magnetized steel needles by placing them inside a coil, the first magnetization of iron by an electric current. In 1824 he found that a spinning copper disc drags a magnet round with it, although copper is not magnetic. Faraday solved this puzzle in 1831: the moving copper carries induced currents, the eddy currents now used in brakes and induction motors.

Goals
  • Compute the field inside a coil and see why iron amplifies it.
  • Derive the eddy-current drag on a conductor moving in a field.
  • Explain Arago’s damping experiment and the effect of slits.

Magnetizing with a coil

Arago reported in late September 1820 that a copper wire carrying current attracts iron filings, which cling around it and drop off when the current stops. Ampère suggested winding the wire into a helix; inside, a steel needle was permanently magnetized. The field inside a long coil of \(n\) turns per metre is \(\mu_0nI\) (see the Ampère course). Soft iron placed in the coil becomes magnetized, and its magnetization adds a field much larger than that of the current alone; William Sturgeon’s horseshoe electromagnet of 1825 exploited this.

Magnetism of rotation

On 22 November 1824 Arago reported that a magnetic needle swinging above a copper plate comes to rest far sooner than one swinging in the open. Inside a thick copper ring a needle made about a quarter as many swings, before its amplitude fell to a fixed value, as it did inside a wooden ring. In 1825 he showed that a copper disc spun beneath a suspended needle drags the needle round. Charles Babbage and John Herschel reversed the experiment, spinning a magnet beneath a pivoted disc, and found that radial slits cut in the disc weaken the effect sharply.

Proposition (eddy-current drag, thin-sheet estimate)

A conducting sheet of conductivity \(\sigma\) and thickness \(t\) moves with speed \(v\) through a region of area \(A\) where a field \(B\) is perpendicular to it. If the induced currents can close freely outside the field region, the retarding force and dissipated power are approximately

\[ F\approx\sigma\,v\,B^2\,tA,\qquad P=Fv\approx\sigma v^2B^2tA. \]

Derivation. In the frame of the sheet, its charges feel the field \(\mathbf v\times\mathbf B\), of size \(vB\), along the sheet perpendicular to \(\mathbf v\). Ohm’s law gives the current density \(J=\sigma vB\) in the field region. The force density \(\mathbf J\times\mathbf B\) has size \(\sigma vB^2\), directed against \(\mathbf v\) (Lenz’s law). Multiply by the volume \(tA\). Charges piling up at the edges of the field region create an electric field opposing \(\mathbf v\times\mathbf B\), so the true force is smaller by a geometric factor of order one. Radial slits block the return paths, so charge accumulates and the currents, and the force, drop: the effect Babbage and Herschel measured.

Exercise 9.1Estimate the drag on a copper sheet (\(\sigma=5.8\times10^7\ \mathrm{S\,m^{-1}}\)), 2 mm thick, moving at 1 m/s past a magnet that produces 0.1 T over 1 cm².

Show solution
\(F\approx5.8\times10^7\cdot1\cdot0.01\cdot0.002\cdot10^{-4}=0.116\ \mathrm N\), more than the weight of a 10 g mass. For a compass needle with fields of order \(10^{-3}\) T at the plate, the force is \(10^4\) times smaller, still enough to damp its swings visibly.

Exercise 9.2An aluminium disc in an electricity meter turns between the poles of a braking magnet. Show that the braking torque is proportional to the angular speed, and explain why that makes the disc’s speed proportional to the driving torque.

Show solution
At radius \(r\) the speed is \(\omega r\), so \(F\propto\sigma\omega rB^2tA\) and the torque \(Fr\propto\omega\). In steady motion the driving torque equals the braking torque \(k\omega\), so \(\omega\) is proportional to the driving torque, which in a meter is proportional to the power used. The number of turns then measures energy.

Exercise 9.3Why did Arago’s needle swing a fixed number of times “before its amplitude fell to a fixed value”, rather than until it stopped? What kind of damping does a force proportional to velocity produce?

Show solution
Velocity-proportional damping gives \(\theta(t)=\theta_0e^{-\gamma t}\cos(\omega t+\phi)\): the amplitude decays exponentially and never strictly reaches zero, so one counts swings until it falls to a chosen value. Arago’s counts measured \(\gamma\), roughly in inverse proportion to the number of swings, giving a quantitative comparison of materials.
Lesson 10

The speed of light in water

For the general reader. The particle theory says light speeds up when it enters water; the wave theory says it slows down. In 1838 Arago designed an experiment to decide between them, using a mirror spinning so fast that it turns measurably while light travels a few metres. His eyesight failed before he could do it. In 1850 Léon Foucault, and separately Hippolyte Fizeau with Louis Breguet, carried it out: light is slower in water, as waves require.

Goals
  • Show why refraction gives opposite predictions in the two theories.
  • Compute the image displacement in a rotating-mirror experiment.
  • Analyse Fizeau’s toothed-wheel measurement of 1849.

Two theories of refraction

In the particle theory, a surface force accelerates light particles perpendicular to the interface, so the tangential velocity is conserved: \(u_1\sin\theta_1=u_2\sin\theta_2\). Snell’s law \(\sin\theta_1=n\sin\theta_2\) then requires \(u_2=nu_1\): faster in the denser medium. In the wave theory, Huygens’s construction with equal phases along the interface gives \(\sin\theta_1/u_1=\sin\theta_2/u_2\), so \(u_2=u_1/n\): slower.

Proposition (rotating mirror)

A mirror turning at angular velocity \(\omega\) reflects light to a fixed mirror at distance \(D\), which returns it to the turning mirror. If light travels at speed \(u\), the returning beam is deflected by the angle

\[ \alpha=2\omega\cdot\frac{2D}{u}=\frac{4\omega D}{u}, \]

relative to the beam that would return if the mirror were still.

Derivation. The round trip takes \(\Delta t=2D/u\), during which the mirror turns by \(\omega\Delta t\). Rotating a mirror by \(\beta\) rotates a reflected beam by \(2\beta\). Arago’s plan sends two beams from the same turning mirror, one through air and one through a tube of water, and compares their displacements side by side. The method needs no measurement of \(\omega\) to decide the question, only which image is displaced more.

Exercise 10.1With \(D=4\) m, a mirror at 800 revolutions per second, and the image viewed at an effective lever arm of 1 m, find the image displacement in air. If 3 m of each path is filled with water (\(n=1.33\)), what is the displacement of the water image?

Show solution
\(\omega=2\pi\cdot800\approx5027\ \mathrm{rad\,s^{-1}}\), \(\Delta t=8/(3\times10^8)\approx2.67\times10^{-8}\) s, \(\alpha=2\omega\Delta t\approx2.68\times10^{-4}\) rad, so about 0.27 mm. With water over 3 m of the 4 m path, \(\Delta t=2(1+3\cdot1.33)/c\approx3.33\times10^{-8}\) s, giving about 0.33 mm. The particle theory predicts the opposite order, about 0.22 mm.

Exercise 10.2In 1849 Fizeau sent light through the gaps of a toothed wheel to a mirror 8633 m away. The returning light was first blocked when the wheel, with 720 teeth, turned 12.6 times per second. Find the speed of light.

Show solution
First eclipse occurs when the wheel advances by half a tooth period during the round trip: \(\frac{2D}{c}=\frac{1}{2Nf}\). So \(c=4DNf=4\cdot8633\cdot720\cdot12.6\approx3.13\times10^8\ \mathrm{m\,s^{-1}}\), about 4% above the modern value.
Part III · Life and legacy
Lesson 11

Secretary, deputy, patron, 1830–1847

In 1830 Arago’s career changed direction. On 7 June the Académie elected him perpetual secretary for the mathematical sciences, succeeding Joseph Fourier, and he gave up his teaching at Polytechnique. After the July Revolution he entered politics as a republican, sitting from 1831 as deputy for the Pyrénées-Orientales. His wife died in 1829, leaving him with their sons; Emmanuel became a lawyer and politician, and Alfred a painter and inspector of fine arts.

As secretary he made the Académie public. He opened its sessions to journalists, and in 1835 he launched the weekly Comptes rendus, which printed short notes within days and changed the pace of scientific publication. His historical éloges of deceased members, among them Fresnel, Ampère, Fourier, James Watt and Thomas Young, remain readable biographies. At the Observatory he took charge of observations in 1834 and became director after Alexis Bouvard’s death in 1843.

He used his influence for science and inventors. In January 1839 he announced Louis Daguerre’s photographic process to the Académie. He persuaded the Chamber to buy the rights and grant Daguerre a pension, so that the process could be given to the world, and on 19 August 1839 he described it in detail at a joint session of the Academies of Sciences and Fine Arts. He supported railways and the electric telegraph and secured public money for the works of Laplace and Fermat. He encouraged the young astronomer Urbain Le Verrier to study the irregularities of Uranus. When Johann Galle found Neptune on 23 September 1846 close to Le Verrier’s predicted position, Arago defended Le Verrier’s priority fiercely against claims for John Couch Adams, and proposed naming the planet after him.

Lesson 12

1848, last years, legacy

When the July Monarchy fell in February 1848, Arago joined the Provisional Government on 24 February as minister of the Navy and the Colonies, and from April also of War. At the Navy he abolished flogging and improved sailors’ rations. He appointed the abolitionist Victor Schœlcher as under-secretary for the colonies, and the government’s decree of 27 April 1848 abolished slavery in all French colonies. On 10 May the new National Assembly elected him to the five-member Executive Commission, which he chaired. It resigned on 24 June during the insurrection of the June Days.

His sight was failing, and he never performed the rotating-mirror experiment himself. After Louis-Napoléon’s coup of December 1851, Arago refused the oath of allegiance required of public servants. The government chose to exempt him and kept him at the Observatory. He attended the Académie for the last time in August 1853, visited his family in Roussillon, and died in Paris on 2 October 1853, aged 67. He was buried in Père Lachaise. His Œuvres complètes, edited by Jean-Augustin Barral, appeared in seventeen volumes from 1854 to 1862.

Legacy

  • Optics: Arago discovered chromatic polarization, optical rotation in quartz and sky polarization, made the polariscope an instrument of astronomy, and supplied the experimental support that established Fresnel’s wave theory.
  • Electromagnetism: he brought Ørsted’s discovery to Paris, with Ampère first magnetized iron and steel with electric currents, and found the eddy-current effects that led Faraday to induction.
  • Institutions: the Comptes rendus, public sessions of the Académie and state support for invention, including photography.
  • Honours: Copley Medal (1825), Rumford Medal (1850), the Prussian Pour le Mérite (1842). The Académie des sciences created the Arago Medal in 1893. His name is on the Eiffel Tower, and bronze medallions bearing his name, Jan Dibbets’s Hommage à Arago, trace the Paris meridian through the city.

Final projectArago often designed or confirmed decisive experiments that others interpreted. Choose two of the bright spot (Lesson 07), magnetism of rotation (Lesson 09) and the speed of light in water (Lesson 10). For each, write a page explaining what the competing theories predicted, why the experiment discriminated between them, and who supplied the final theoretical explanation.

Reference

Connections

People linked to François Arago across this collection. A name without a link has no page here yet. See François Arago in the network of all 337 lives →

Students

Influenced by

Influenced

Colleagues and collaborators

Rivals

Friends

Family

  • Emmanuel Arago
  • Jacques Arago

Also mentioned in this life

Fields

On CoursesHub

Reference

Sources and further reading

Biography

  1. J. J. O’Connor and E. F. Robertson, François Arago, MacTutor History of Mathematics.
  2. François Arago, Wikipedia.
  3. D. W. Strickland, François Arago (February 26, 1786 – October 2, 1853), MacTutor.
  4. F. Arago, Histoire de ma jeunesse, in Œuvres complètes, vol. 1, 1854 (his own account of the meridian expedition).
  5. J. Lequeux, François Arago, un savant généreux, EDP Sciences / Observatoire de Paris, 2008; English edition Springer, 2016.
  6. M. Daumas, Arago, la jeunesse de la science, Gallimard, 1943.

Physics

  1. F. Arago and A. Fresnel, Mémoire sur l’action que les rayons de lumière polarisés exercent les uns sur les autres, Annales de chimie et de physique 10 (1819).
  2. F. Arago, Expériences relatives à l’aimantation du fer et de l’acier par l’action du courant voltaïque, Annales de chimie et de physique 15 (1820).
  3. Arago spot and Arago’s rotations, Wikipedia.
  4. W. Whewell, History of the Inductive Sciences, 3rd ed., 1858, vol. 2, on the polarization of light.
  5. K. Alder, The Measure of All Things: The Seven-Year Odyssey That Transformed the World, Free Press, 2002.
  6. J. D. Jackson, Classical Electrodynamics, 3rd ed., Wiley, 1999 (eddy currents, scattering).
  7. M. Born and E. Wolf, Principles of Optics, Cambridge, 7th ed., 1999 (polarization, Fresnel zones).